blob: 54d1802efd31a38285719422de855d5135055aeb [file] [log] [blame]
// SPDX-License-Identifier: GPL-2.0
#include <linux/export.h>
#include <linux/kernel.h>
#include <linux/math64.h>
u64 mul_u64_u64_div_u64(u64 a, u64 b, u64 c)
{
u64 res = 0, div, rem;
int shift;
/* can a * b overflow ? */
if (ilog2(a) + ilog2(b) > 62) {
/*
* (b * a) / c is equal to
*
* (b / c) * a +
* (b % c) * a / c
*
* if nothing overflows. Can the 1st multiplication
* overflow? Yes, but we do not care: this can only
* happen if the end result can't fit in u64 anyway.
*
* So the code below does
*
* res = (b / c) * a;
* b = b % c;
*/
div = div64_u64_rem(b, c, &rem);
res = div * a;
b = rem;
shift = ilog2(a) + ilog2(b) - 62;
if (shift > 0) {
/* drop precision */
b >>= shift;
c >>= shift;
if (!c)
return res;
}
}
return res + div64_u64(a * b, c);
}
EXPORT_SYMBOL_GPL(mul_u64_u64_div_u64);