treewide: Define \pct for percent sign and use it instead of "\,\%"
As mentioned below "---" in the patch submission of commit c6689857b6e6
("advsync: Add narrow space in front of percent sign") [1], in the hope
of making similar issues less likely to happen in the future, define
a macro for this pattern in the former way (\pct) and make use of it
treewide.
Link: https://lore.kernel.org/perfbook/4884acc4-63b4-4b6f-b0bf-c236c193e2ae@gmail.com/ [1]
Signed-off-by: Akira Yokosawa <akiyks@gmail.com>
Signed-off-by: Paul E. McKenney <paulmck@kernel.org>
diff --git a/SMPdesign/SMPdesign.tex b/SMPdesign/SMPdesign.tex
index 0bc0bcb..246182c 100644
--- a/SMPdesign/SMPdesign.tex
+++ b/SMPdesign/SMPdesign.tex
@@ -1264,7 +1264,7 @@
practice~\cite{McKenney01e}, especially given today's large memories.
For example, in most systems, it is quite reasonable to set
\co{TARGET_POOL_SIZE} to 100, in which case allocations and frees
-are guaranteed to be confined to per-thread pools at least 99\,\% of
+are guaranteed to be confined to per-thread pools at least 99\pct\ of
the time.
As can be seen from the figure, the situations where the common-case
diff --git a/SMPdesign/beyond.tex b/SMPdesign/beyond.tex
index e90298c..fa6218d 100644
--- a/SMPdesign/beyond.tex
+++ b/SMPdesign/beyond.tex
@@ -462,8 +462,8 @@
\end{figure}
Further investigation showed that
-PART sometimes visited fewer than 2\,\% of the maze's cells,
-while SEQ and PWQ never visited fewer than about 9\,\%.
+PART sometimes visited fewer than 2\pct\ of the maze's cells,
+while SEQ and PWQ never visited fewer than about 9\pct.
The reason for this difference is shown by
\cref{fig:SMPdesign:Reason for Small Visit Percentages}.
If the thread traversing the solution from the upper left reaches
@@ -545,11 +545,11 @@
Cache alignment and padding often improves performance by reducing
\IX{false sharing}.
However, for these maze-solution algorithms, aligning and padding the
-maze-cell array \emph{degrades} performance by up to 42\,\% for 1000x1000 mazes.
+maze-cell array \emph{degrades} performance by up to 42\pct\ for 1000x1000 mazes.
Cache locality is more important than avoiding
false sharing, especially for large mazes.
For smaller 20-by-20 or 50-by-50 mazes, aligning and padding can produce
-up to a 40\,\% performance improvement for PART,
+up to a 40\pct\ performance improvement for PART,
but for these small sizes, SEQ performs better anyway because there
is insufficient time for PART to make up for the overhead of
thread creation and destruction.
@@ -580,7 +580,7 @@
As can be seen in
\cref{fig:SMPdesign:Partitioned Coroutines},
this coroutine algorithm (COPART) is quite effective, with the performance
-on one thread being within about 30\,\% of PART on two threads
+on one thread being within about 30\pct\ of PART on two threads
(\path{maze_2seq.c}).
\subsection{Performance Comparison II}
diff --git a/advsync/advsync.tex b/advsync/advsync.tex
index 31731f6..df0d44f 100644
--- a/advsync/advsync.tex
+++ b/advsync/advsync.tex
@@ -416,7 +416,7 @@
bound.
\item Real-time forward-progress guarantees are often
probabilistic, as in the soft-real-time guarantee that
- ``at least 99.9\,\% of the time, scheduling latency must
+ ``at least 99.9\pct\ of the time, scheduling latency must
be less than 100 microseconds.''
In contrast, many of NBS's forward-progress guarantees are
unconditional, which can impose additional unnecessary complexity
@@ -458,11 +458,11 @@
As a rough rule of thumb, latency increases as the reciprocal
of the idle time.
In other words, if a nearly idle system has
- latency $T$, then a 50\,\% idle system will have latency $2 T$, a
- 10\,\% idle (90\,\% utilized) system will have latency $10 T$, a 1\,\%
- idle system (99\,\% utilized) will have latency $100 T$, and so on.
+ latency $T$, then a 50\pct\ idle system will have latency $2 T$, a
+ 10\pct\ idle (90\pct\ utilized) system will have latency $10 T$, a 1\pct\
+ idle system (99\pct\ utilized) will have latency $100 T$, and so on.
This situation means that many latency-sensitive systems will
- actively limit load, for example, to 50\,\%.
+ actively limit load, for example, to 50\pct.
\item In the not-uncommon case where a given computed result is nice
to have rather than critically important, use of timeouts can
cause a blocking operation to have non-blocking properties that
diff --git a/advsync/rt.tex b/advsync/rt.tex
index b154030..9331f5c 100644
--- a/advsync/rt.tex
+++ b/advsync/rt.tex
@@ -57,7 +57,7 @@
We might therefore say that a given soft real-time application must meet
its response-time requirements at least some fraction of the time, for
example, we might say that it must execute in less than 20 microseconds
-99.9\,\% of the time.
+99.9\pct\ of the time.
This of course raises the question of what is to be done when the application
fails to meet its response-time requirements.
@@ -278,7 +278,7 @@
Overloading can also degrade response times due to queueing effects,
so it is not unusual for real-time systems to overprovision CPU bandwidth,
-so that a running system has (say) 80\,\% idle time.
+so that a running system has (say) 80\pct\ idle time.
This approach also applies to storage and networking devices.
In some cases, separate storage and networking hardware might be reserved
for the sole use of high-priority portions of the real-time application.
@@ -362,7 +362,7 @@
For each such operation, these constraints might include a maximum
response time (and possibly also a minimum response time) and a
probability of meeting that response time.
-A probability of 100\,\% indicates that the corresponding operation
+A probability of 100\pct\ indicates that the corresponding operation
must provide hard real-time service.
In some cases, both the response times and the required probabilities of
@@ -1719,7 +1719,7 @@
latencies are provided only to the highest-priority threads.
\item Sufficient bandwidth to support the workload.
An implementation rule supporting this constraint might be
- ``There will be at least 50\,\% idle time on all CPUs
+ ``There will be at least 50\pct\ idle time on all CPUs
during normal operation,''
or, more formally, ``The offered load will be sufficiently low
to allow the workload to be schedulable at all times.''
diff --git a/appendix/styleguide/styleguide.tex b/appendix/styleguide/styleguide.tex
index 9df2535..b52f97f 100644
--- a/appendix/styleguide/styleguide.tex
+++ b/appendix/styleguide/styleguide.tex
@@ -202,7 +202,7 @@
symbols.
\begin{quote}
- 50\,\% possibility, rather than 50\% possibility.
+ 50\pct\ possibility, rather than 50\% possibility.
\end{quote}
\subsubsection{Font Style}
diff --git a/count/count.tex b/count/count.tex
index 46b20e8..18619bf 100644
--- a/count/count.tex
+++ b/count/count.tex
@@ -53,7 +53,7 @@
whatever ``true value'' might mean in this context.
However, the value read out should maintain roughly the same
absolute error over time.
- For example, a 1\,\% error might be just fine when the count
+ For example, a 1\pct\ error might be just fine when the count
is on the order of a million or so, but might be absolutely
unacceptable once the count reaches a trillion.
See \cref{sec:count:Statistical Counters}.
@@ -199,7 +199,7 @@
285,824,000 times, but the final value of the counter was only
35,385,525.
Although approximation does have a large place in computing, loss of
-87\,\% of the counts is a bit excessive.
+87\pct\ of the counts is a bit excessive.
\QuickQuizSeries{%
\QuickQuizB{
diff --git a/cpu/hwfreelunch.tex b/cpu/hwfreelunch.tex
index a7c033c..15bc3b2 100644
--- a/cpu/hwfreelunch.tex
+++ b/cpu/hwfreelunch.tex
@@ -170,13 +170,13 @@
Although the speed of light would be a hard limit, the fact is that
semiconductor devices are limited by the speed of electricity rather
than that of light, given that electric waves in semiconductor materials
-move at between 3\,\% and 30\,\% of the speed of light in a vacuum.
+move at between 3\pct\ and 30\pct\ of the speed of light in a vacuum.
The use of copper connections on silicon devices is one way to increase
the speed of electricity, and it is quite possible that additional
advances will push closer still to the actual speed of light.
In addition, there have been some experiments with tiny optical fibers
as interconnects within and between chips, based on the fact that
-the speed of light in glass is more than 60\,\% of the speed of light
+the speed of light in glass is more than 60\pct\ of the speed of light
in a vacuum.
One obstacle to such optical fibers is the inefficiency conversion
between electricity and light and vice versa, resulting in both
diff --git a/debugging/debugging.tex b/debugging/debugging.tex
index 75226a4..f285ebc 100644
--- a/debugging/debugging.tex
+++ b/debugging/debugging.tex
@@ -1287,18 +1287,18 @@
\subsection{Statistics for Discrete Testing}
\label{sec:debugging:Statistics for Discrete Testing}
-Suppose a bug has a 10\,\% chance of occurring in a given run and that
+Suppose a bug has a 10\pct\ chance of occurring in a given run and that
we do five runs.
How do we compute the probability of at least one run failing?
Here is one way:
\begin{enumerate}
-\item Compute the probability of a given run succeeding, which is 90\,\%.
+\item Compute the probability of a given run succeeding, which is 90\pct.
\item Compute the probability of all five runs succeeding, which
- is 0.9 raised to the fifth power, or about 59\,\%.
+ is 0.9 raised to the fifth power, or about 59\pct.
\item Because either all five runs succeed, or at least one fails,
- subtract the 59\,\% expected success rate from 100\,\%, yielding
- a 41\,\% expected failure rate.
+ subtract the 59\pct\ expected success rate from 100\pct, yielding
+ a 41\pct\ expected failure rate.
\end{enumerate}
For those preferring formulas, call the probability of a single failure $f$.
@@ -1318,36 +1318,36 @@
\QuickQuiz{
Say what???
- When I plug the earlier five-test 10\,\%-failure-rate example into
- the formula, I get 59,050\,\% and that just doesn't make sense!!!
+ When I plug the earlier five-test 10\pct-failure-rate example into
+ the formula, I get 59,050\pct\ and that just doesn't make sense!!!
}\QuickQuizAnswer{
You are right, that makes no sense at all.
Remember that a probability is a number between zero and one,
so that you need to divide a percentage by 100 to get a
probability.
- So 10\,\% is a probability of 0.1, which gets a probability
- of 0.4095, which rounds to 41\,\%, which quite sensibly
+ So 10\pct\ is a probability of 0.1, which gets a probability
+ of 0.4095, which rounds to 41\pct, which quite sensibly
matches the earlier result.
}\QuickQuizEnd
-So suppose that a given test has been failing 10\,\% of the time.
-How many times do you have to run the test to be 99\,\% sure that
+So suppose that a given test has been failing 10\pct\ of the time.
+How many times do you have to run the test to be 99\pct\ sure that
your alleged fix actually helped?
Another way to ask this question is ``How many times would we need
-to run the test to cause the probability of failure to rise above 99\,\%?''
+to run the test to cause the probability of failure to rise above 99\pct?''
After all, if we were to run the test enough times that the probability
-of seeing at least one failure becomes 99\,\%, and none of these test
+of seeing at least one failure becomes 99\pct, and none of these test
runs fail,
-there is only 1\,\% probability of this ``success'' being due to dumb luck.
+there is only 1\pct\ probability of this ``success'' being due to dumb luck.
And if we plug $f=0.1$ into
\cref{eq:debugging:Binomial Failure Rate} and vary $n$,
-we find that 43 runs gives us a 98.92\,\% chance of at least one test failing
-given the original 10\,\% per-test failure rate,
-while 44 runs gives us a 99.03\,\% chance of at least one test failing.
+we find that 43 runs gives us a 98.92\pct\ chance of at least one test failing
+given the original 10\pct\ per-test failure rate,
+while 44 runs gives us a 99.03\pct\ chance of at least one test failing.
So if we run the test on our fix 44 times and see no failures, there
-is a 99\,\% probability that our fix really did help.
+is a 99\pct\ probability that our fix really did help.
But repeatedly plugging numbers into
\cref{eq:debugging:Binomial Failure Rate}
@@ -1369,7 +1369,7 @@
Plugging $f=0.1$ and $F_n=0.99$ into
\cref{eq:debugging:Binomial Number of Tests Required}
gives 43.7, meaning that we need 44 consecutive successful test
-runs to be 99\,\% certain that our fix was a real improvement.
+runs to be 99\pct\ certain that our fix was a real improvement.
This matches the number obtained by the previous method, which
is reassuring.
@@ -1394,9 +1394,9 @@
\Cref{fig:debugging:Number of Tests Required for 99 Percent Confidence Given Failure Rate}
shows a plot of this function.
Not surprisingly, the less frequently each test run fails, the more
-test runs are required to be 99\,\% confident that the bug has been
+test runs are required to be 99\pct\ confident that the bug has been
at least partially fixed.
-If the bug caused the test to fail only 1\,\% of the time, then a
+If the bug caused the test to fail only 1\pct\ of the time, then a
mind-boggling 458 test runs are required.
As the failure probability decreases, the number of test runs required
increases, going to infinity as the failure probability goes to zero.
@@ -1404,18 +1404,18 @@
The moral of this story is that when you have found a rarely occurring
bug, your testing job will be much easier if you can come up with
a carefully targeted test (or ``reproducer'') with a much higher failure rate.
-For example, if your reproducer raised the failure rate from 1\,\%
-to 30\,\%, then the number of runs required for 99\,\% confidence
+For example, if your reproducer raised the failure rate from 1\pct\
+to 30\pct, then the number of runs required for 99\pct\ confidence
would drop from 458 to a more tractable 13.
-But these thirteen test runs would only give you 99\,\% confidence that
+But these thirteen test runs would only give you 99\pct\ confidence that
your fix had produced ``some improvement''.
-Suppose you instead want to have 99\,\% confidence that your fix reduced
+Suppose you instead want to have 99\pct\ confidence that your fix reduced
the failure rate by an order of magnitude.
How many failure-free test runs are required?
-An order of magnitude improvement from a 30\,\% failure rate would be
-a 3\,\% failure rate.
+An order of magnitude improvement from a 30\pct\ failure rate would be
+a 3\pct\ failure rate.
Plugging these numbers into
\cref{eq:debugging:Binomial Number of Tests Required} yields:
@@ -1439,14 +1439,14 @@
But suppose that you have a continuous test that fails about three
times every ten hours, and that you fix the bug that you believe was
causing the failure.
-How long do you have to run this test without failure to be 99\,\% certain
+How long do you have to run this test without failure to be 99\pct\ certain
that you reduced the probability of failure?
Without doing excessive violence to statistics, we could simply
-redefine a one-hour run to be a discrete test that has a 30\,\%
+redefine a one-hour run to be a discrete test that has a 30\pct\
probability of failure.
Then the results of in the previous section tell us that if the test
-runs for 13 hours without failure, there is a 99\,\% probability that
+runs for 13 hours without failure, there is a 99\pct\ probability that
our fix actually improved the program's reliability.
A dogmatic statistician might not approve of this approach, but the sad
@@ -1476,9 +1476,9 @@
Let's rework the example from
\cref{sec:debugging:Statistics Abuse for Discrete Testing}
using the Poisson distribution.
-Recall that this example involved an alleged fix for a bug with a 30\,\%
+Recall that this example involved an alleged fix for a bug with a 30\pct\
failure rate per hour.
-If we need to be 99\,\% certain that the fix actually reduced the failure
+If we need to be 99\pct\ certain that the fix actually reduced the failure
rate, how long an error-free test run is required?
In this case, $m$ is zero, so that
\cref{eq:debugging:Poisson Probability} reduces to:
@@ -1495,11 +1495,11 @@
\end{equation}
Because we get $0.3$ failures per hour, the number of hours required
-is $4.6/0.3 = 14.3$, which is within 10\,\% of the 13 hours
+is $4.6/0.3 = 14.3$, which is within 10\pct\ of the 13 hours
calculated using the method in
\cref{sec:debugging:Statistics Abuse for Discrete Testing}.
Given that you normally won't know your failure rate to anywhere near
-10\,\%, the simpler method described in
+10\pct, the simpler method described in
\cref{sec:debugging:Statistics Abuse for Discrete Testing}
is almost always good and sufficient.
@@ -1507,7 +1507,7 @@
testing are encouraged to read on.
More generally, if we have $n$ failures per unit time, and we want to
-be $P$\,\% certain that a fix reduced the failure rate, we can use the
+be $P$\pct\ certain that a fix reduced the failure rate, we can use the
following formula:
\begin{equation}
@@ -1518,7 +1518,7 @@
\QuickQuiz{
Suppose that a bug causes a test failure three times per hour
on average.
- How long must the test run error-free to provide 99.9\,\%
+ How long must the test run error-free to provide 99.9\pct\
confidence that the fix significantly reduced the probability
of failure by at least a little bit?
}\QuickQuizAnswer{
@@ -1529,7 +1529,7 @@
T = - \frac{1}{3} \ln \frac{100 - 99.9}{100} = 2.3
\end{equation}
- If the test runs without failure for 2.3 hours, we can be 99.9\,\%
+ If the test runs without failure for 2.3 hours, we can be 99.9\pct\
certain that the fix reduced (by at least some small amount)
the probability of failure.
}\QuickQuizEnd
@@ -1580,7 +1580,7 @@
\end{equation}
Continuing our example with $m=2$ and $\lambda=24$, this gives a confidence
-of about 0.999999988, or equivalently, 99.9999988\,\%.
+of about 0.999999988, or equivalently, 99.9999988\pct.
This level of confidence should satisfy all but the purest of purists.
But what if we are interested not in ``some relationship'' to the bug,
@@ -1588,7 +1588,7 @@
expected frequency of occurrence?
Then we divide $\lambda$ by ten, and plug $m=2$ and $\lambda=2.4$ into
\cref{eq:debugging:Possion Confidence},
-which gives but a 90.9\,\% confidence level.
+which gives but a 90.9\pct\ confidence level.
This illustrates the sad fact that increasing either statistical
confidence or degree of improvement, let alone both, can be quite
expensive.
@@ -1648,10 +1648,10 @@
Another approach is to recognize that in this real world,
it is not all that useful to compute (say) the duration of a test
- having two or fewer errors that would give a 76.8\,\% confidence
+ having two or fewer errors that would give a 76.8\pct\ confidence
of a 349.2x improvement in reliability.
Instead, human beings tend to focus on specific values, for
- example, a 95\,\% confidence of a 10x improvement.
+ example, a 95\pct\ confidence of a 10x improvement.
People also greatly prefer error-free test runs, and so should
you because doing so reduces your required test durations.
Therefore, it is quite possible that the values in
@@ -1662,7 +1662,7 @@
error-free test duration in terms of the expected time for
a single error to appear.
So if your pre-fix testing suffered one failure per hour, and the
- powers that be require a 95\,\% confidence of a 10x improvement,
+ powers that be require a 95\pct\ confidence of a 10x improvement,
you need a 30-hour error-free run.
Alternatively, you can use the rough-and-ready method described in
@@ -1991,7 +1991,7 @@
For example, a low-probability bug in RCU priority boosting occurred
roughly once every hundred hours of focused \co{rcutorture} testing.
Because it would take almost 500 hours of failure-free testing to be
-99\,\% certain that the bug's probability had been significantly reduced,
+99\pct\ certain that the bug's probability had been significantly reduced,
the \co{git bisect} process
to find the failure would be painfully slow---or would require an extremely
large test farm.
@@ -2221,12 +2221,12 @@
Although I do heartily salute your spirit and aspirations,
you are forgetting that there may be high costs due to delays
in the program's completion.
- For an extreme example, suppose that a 30\,\% performance shortfall
+ For an extreme example, suppose that a 30\pct\ performance shortfall
from a single-threaded application is causing one person to die
each day.
Suppose further that in a day you could hack together a
quick and dirty
- parallel program that ran 50\,\% faster on an eight-CPU system.
+ parallel program that ran 50\pct\ faster on an eight-CPU system.
This is of course horrible scalability, given that the seven
additional CPUs provide only half a CPU's worth of additional
performance.
@@ -2698,7 +2698,7 @@
\item [\lopt{relerr}\nf{:}] Relative measurement error.
The script assumes that values that differ by less than this
error are for all intents and purposes equal.
- This defaults to 0.01, which is equivalent to 1\,\%.
+ This defaults to 0.01, which is equivalent to 1\pct.
\item [\lopt{trendbreak}\nf{:}] Ratio of inter-element spacing
constituting a break in the trend of the data.
For example, if the average spacing in the data accepted so far
@@ -2769,7 +2769,7 @@
}\QuickQuizAnswerB{
Because mean and standard deviation were not designed to do this job.
To see this, try applying mean and standard deviation to the
- following data set, given a 1\,\% relative error in measurement:
+ following data set, given a 1\pct\ relative error in measurement:
\begin{quote}
49,548.4 49,549.4 49,550.2 49,550.9 49,550.9 49,551.0
@@ -2906,7 +2906,7 @@
the world?
In that case, a bug that occurs once every million years on a single system
will be encountered more than 50 times per day across the installed base.
-A test with a 50\,\% chance of encountering this bug in a one-hour run
+A test with a 50\pct\ chance of encountering this bug in a one-hour run
would need to increase that bug's probability of occurrence by more than
ten orders of magnitude, which poses a severe challenge to
today's testing methodologies.
diff --git a/defer/rcuusage.tex b/defer/rcuusage.tex
index 3db94b2..6225c67 100644
--- a/defer/rcuusage.tex
+++ b/defer/rcuusage.tex
@@ -1619,7 +1619,7 @@
Of course, there are some reader-writer-locking use cases for which
RCU's weakened semantics are inappropriate, but experience in the Linux
-kernel indicates that more than 80\% of reader-writer locks can in fact
+kernel indicates that more than 80\pct\ of reader-writer locks can in fact
be replaced by RCU\@.
For example, a common reader-writer-locking use case computes some value
while holding the lock and then uses that value after releasing that lock.
diff --git a/formal/dyntickrcu.tex b/formal/dyntickrcu.tex
index efd1108..e0b2d45 100644
--- a/formal/dyntickrcu.tex
+++ b/formal/dyntickrcu.tex
@@ -1112,7 +1112,7 @@
\end{quote}
This means that any attempt to optimize the production of code should
- place at least 66\,\% of its emphasis on optimizing the debugging process,
+ place at least 66\pct\ of its emphasis on optimizing the debugging process,
even at the expense of increasing the time and effort spent coding.
Incremental coding and testing is one way to optimize the debugging
process, at the expense of some increase in coding effort.
diff --git a/formal/spinhint.tex b/formal/spinhint.tex
index cc092bc..17ee2a5 100644
--- a/formal/spinhint.tex
+++ b/formal/spinhint.tex
@@ -290,7 +290,7 @@
run \co{top} in one window and \co{./pan} in another.
Keep the focus on the \co{./pan} window so that you can quickly
kill execution if need be.
- As soon as CPU time drops much below 100\,\%, kill \co{./pan}.
+ As soon as CPU time drops much below 100\pct, kill \co{./pan}.
If you have removed focus from the window running \co{./pan},
you may wait a long time for the windowing system to grab
enough memory to do anything for you.
@@ -963,7 +963,7 @@
\end{listing}
\QuickQuiz{
- A compression rate of 0.48\,\% corresponds to a 200-to-1 decrease
+ A compression rate of 0.48\pct\ corresponds to a 200-to-1 decrease
in memory occupied by the states!
Is the state-space search \emph{really} exhaustive???
}\QuickQuizAnswer{
diff --git a/future/formalregress.tex b/future/formalregress.tex
index b674d61..786fd7a 100644
--- a/future/formalregress.tex
+++ b/future/formalregress.tex
@@ -462,7 +462,7 @@
The answer is that the reliability \emph{decreases}.
To see this, keep in mind that historical experience indicates that
-about 7\,\% of fixes introduce a new bug~\cite{RexBlack2012SQA}.
+about 7\pct\ of fixes introduce a new bug~\cite{RexBlack2012SQA}.
Therefore, fixing the 100 bugs, which had a combined mean time to failure
(MTBF) of about 10,000 years, will introduce seven more bugs.
Historical statistics indicate that each new bug will have an MTBF
@@ -479,7 +479,7 @@
}\QuickQuizAnswerB{
We don't, but it does not matter.
- To see this, note that the 7\,\% figure only applies to injected
+ To see this, note that the 7\pct\ figure only applies to injected
bugs that were subsequently located:
It necessarily ignores any injected bugs that were never found.
Therefore, the MTBF statistics of known bugs is likely to be
diff --git a/future/htm.tex b/future/htm.tex
index c9e5467..9a02225 100644
--- a/future/htm.tex
+++ b/future/htm.tex
@@ -1214,7 +1214,7 @@
is to use RCU for read-only traversals and HTM
only for the actual updates themselves.
This combination outperformed other transactional-memory techniques by
-up to 220\,\%, a speedup similar to that observed by
+up to 220\pct, a speedup similar to that observed by
Howard and Walpole~\cite{PhilHoward2011RCUTMRBTree}
when they combined RCU with STM\@.
In both cases, the weak atomicity is implemented in software rather than
diff --git a/future/tm.tex b/future/tm.tex
index db08bcc..db38ca8 100644
--- a/future/tm.tex
+++ b/future/tm.tex
@@ -767,8 +767,8 @@
the transaction, and everything works out perfectly.
In practice, a number of non-obvious complications~\cite{Volos2008TRANSACT}
can arise, depending on implementation details of the TM system.
-These complications can be resolved, but at the cost of a 45\,\% increase in
-overhead for locks acquired outside of transactions and a 300\,\% increase
+These complications can be resolved, but at the cost of a 45\pct\ increase in
+overhead for locks acquired outside of transactions and a 300\pct\ increase
in overhead for locks acquired within transactions.
Although these overheads might be acceptable for transactional
programs containing small amounts of locking, they are often completely
diff --git a/intro/intro.tex b/intro/intro.tex
index e00462b..ae47a52 100644
--- a/intro/intro.tex
+++ b/intro/intro.tex
@@ -442,7 +442,7 @@
of millions of dollars at
a time when engineering salaries were but a few thousand dollars a year.
If dedicating a team of ten engineers to such a machine would improve
-its performance, even by only 10\,\%, then their salaries
+its performance, even by only 10\pct, then their salaries
would be repaid many times over.
One such machine was the CSIRAC, the oldest still-intact stored-program
@@ -917,11 +917,11 @@
general results.
Furthermore, given that the normal range of programmer productivity
spans more than an order of magnitude, it is unrealistic to expect
-an affordable study to be capable of detecting (say) a 10\,\% difference
+an affordable study to be capable of detecting (say) a 10\pct\ difference
in productivity.
Although the multiple-order-of-magnitude differences that such studies
\emph{can} reliably detect are extremely valuable, the most impressive
-improvements tend to be based on a long series of 10\,\% improvements.
+improvements tend to be based on a long series of 10\pct\ improvements.
We must therefore take a different approach.
diff --git a/perfbook-lt.tex b/perfbook-lt.tex
index 25f16ff..1c7ea47 100644
--- a/perfbook-lt.tex
+++ b/perfbook-lt.tex
@@ -90,7 +90,7 @@
\setlength{\epigraphwidth}{2.6in}
\usepackage[xspace]{ellipsis}
\usepackage{braket} % for \ket{} macro in QC section
-\usepackage{siunitx} % for \num{} macro
+\usepackage{siunitx} % for \num{} macro and \unit{} (such as \percent)
\sisetup{group-minimum-digits=4,group-separator={,},group-digits=integer}
\usepackage{multirow}
\usepackage{noindentafter}
@@ -612,6 +612,7 @@
\newcommand{\IRQ}{IRQ}
%\newcommand{\IRQ}{irq} % For those who prefer "irq"
\newcommand{\rt}{\mbox{-rt}} % to prevent line break behind "-"
+\newcommand{\pct}{\,\unit{\percent}}
\let\epigraphorig\epigraph
\renewcommand{\epigraph}[2]{\epigraphorig{\biolinum\emph{#1}}{\biolinum\scshape\footnotesize #2}}
diff --git a/summary.tex b/summary.tex
index 1837969..15f17d0 100644
--- a/summary.tex
+++ b/summary.tex
@@ -243,7 +243,7 @@
Some years later, this employer choose to appoint someone with more
useful experience and fewer sound bites.
That someone was also on a panel, and during that session he looked
-directly at me when he stated that parallel programming was perhaps 5\%
+directly at me when he stated that parallel programming was perhaps 5\pct\
more difficult than sequential programming.
For the rest of us, when someone tries to show us a solution to pressing
diff --git a/toolsoftrade/toolsoftrade.tex b/toolsoftrade/toolsoftrade.tex
index bb7c8cc..e1b24f3 100644
--- a/toolsoftrade/toolsoftrade.tex
+++ b/toolsoftrade/toolsoftrade.tex
@@ -911,7 +911,7 @@
This situation will only get worse as you add CPUs.
Note also the logscale y-axis.
Even though the 10,000\,microsecond trace appears quite ideal, it has
-in fact degraded by about 10\,\% from ideal.
+in fact degraded by about 10\pct\ from ideal.
\QuickQuizSeries{%
\QuickQuizB{
