|  | /* | 
|  | * Copyright (C) 2007 Oracle.  All rights reserved. | 
|  | * | 
|  | * This program is free software; you can redistribute it and/or | 
|  | * modify it under the terms of the GNU General Public | 
|  | * License v2 as published by the Free Software Foundation. | 
|  | * | 
|  | * This program is distributed in the hope that it will be useful, | 
|  | * but WITHOUT ANY WARRANTY; without even the implied warranty of | 
|  | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU | 
|  | * General Public License for more details. | 
|  | * | 
|  | * You should have received a copy of the GNU General Public | 
|  | * License along with this program; if not, write to the | 
|  | * Free Software Foundation, Inc., 59 Temple Place - Suite 330, | 
|  | * Boston, MA 021110-1307, USA. | 
|  | */ | 
|  |  | 
|  | #include <linux/sched.h> | 
|  | #include "ctree.h" | 
|  | #include "disk-io.h" | 
|  | #include "print-tree.h" | 
|  | #include "transaction.h" | 
|  | #include "locking.h" | 
|  |  | 
|  | /* | 
|  | * Defrag all the leaves in a given btree. | 
|  | * Read all the leaves and try to get key order to | 
|  | * better reflect disk order | 
|  | */ | 
|  |  | 
|  | int btrfs_defrag_leaves(struct btrfs_trans_handle *trans, | 
|  | struct btrfs_root *root) | 
|  | { | 
|  | struct btrfs_path *path = NULL; | 
|  | struct btrfs_key key; | 
|  | int ret = 0; | 
|  | int wret; | 
|  | int level; | 
|  | int next_key_ret = 0; | 
|  | u64 last_ret = 0; | 
|  | u64 min_trans = 0; | 
|  |  | 
|  | if (root->fs_info->extent_root == root) { | 
|  | /* | 
|  | * there's recursion here right now in the tree locking, | 
|  | * we can't defrag the extent root without deadlock | 
|  | */ | 
|  | goto out; | 
|  | } | 
|  |  | 
|  | if (!test_bit(BTRFS_ROOT_REF_COWS, &root->state)) | 
|  | goto out; | 
|  |  | 
|  | path = btrfs_alloc_path(); | 
|  | if (!path) | 
|  | return -ENOMEM; | 
|  |  | 
|  | level = btrfs_header_level(root->node); | 
|  |  | 
|  | if (level == 0) | 
|  | goto out; | 
|  |  | 
|  | if (root->defrag_progress.objectid == 0) { | 
|  | struct extent_buffer *root_node; | 
|  | u32 nritems; | 
|  |  | 
|  | root_node = btrfs_lock_root_node(root); | 
|  | btrfs_set_lock_blocking(root_node); | 
|  | nritems = btrfs_header_nritems(root_node); | 
|  | root->defrag_max.objectid = 0; | 
|  | /* from above we know this is not a leaf */ | 
|  | btrfs_node_key_to_cpu(root_node, &root->defrag_max, | 
|  | nritems - 1); | 
|  | btrfs_tree_unlock(root_node); | 
|  | free_extent_buffer(root_node); | 
|  | memset(&key, 0, sizeof(key)); | 
|  | } else { | 
|  | memcpy(&key, &root->defrag_progress, sizeof(key)); | 
|  | } | 
|  |  | 
|  | path->keep_locks = 1; | 
|  |  | 
|  | ret = btrfs_search_forward(root, &key, path, min_trans); | 
|  | if (ret < 0) | 
|  | goto out; | 
|  | if (ret > 0) { | 
|  | ret = 0; | 
|  | goto out; | 
|  | } | 
|  | btrfs_release_path(path); | 
|  | /* | 
|  | * We don't need a lock on a leaf. btrfs_realloc_node() will lock all | 
|  | * leafs from path->nodes[1], so set lowest_level to 1 to avoid later | 
|  | * a deadlock (attempting to write lock an already write locked leaf). | 
|  | */ | 
|  | path->lowest_level = 1; | 
|  | wret = btrfs_search_slot(trans, root, &key, path, 0, 1); | 
|  |  | 
|  | if (wret < 0) { | 
|  | ret = wret; | 
|  | goto out; | 
|  | } | 
|  | if (!path->nodes[1]) { | 
|  | ret = 0; | 
|  | goto out; | 
|  | } | 
|  | /* | 
|  | * The node at level 1 must always be locked when our path has | 
|  | * keep_locks set and lowest_level is 1, regardless of the value of | 
|  | * path->slots[1]. | 
|  | */ | 
|  | BUG_ON(path->locks[1] == 0); | 
|  | ret = btrfs_realloc_node(trans, root, | 
|  | path->nodes[1], 0, | 
|  | &last_ret, | 
|  | &root->defrag_progress); | 
|  | if (ret) { | 
|  | WARN_ON(ret == -EAGAIN); | 
|  | goto out; | 
|  | } | 
|  | /* | 
|  | * Now that we reallocated the node we can find the next key. Note that | 
|  | * btrfs_find_next_key() can release our path and do another search | 
|  | * without COWing, this is because even with path->keep_locks = 1, | 
|  | * btrfs_search_slot() / ctree.c:unlock_up() does not keeps a lock on a | 
|  | * node when path->slots[node_level - 1] does not point to the last | 
|  | * item or a slot beyond the last item (ctree.c:unlock_up()). Therefore | 
|  | * we search for the next key after reallocating our node. | 
|  | */ | 
|  | path->slots[1] = btrfs_header_nritems(path->nodes[1]); | 
|  | next_key_ret = btrfs_find_next_key(root, path, &key, 1, | 
|  | min_trans); | 
|  | if (next_key_ret == 0) { | 
|  | memcpy(&root->defrag_progress, &key, sizeof(key)); | 
|  | ret = -EAGAIN; | 
|  | } | 
|  | out: | 
|  | btrfs_free_path(path); | 
|  | if (ret == -EAGAIN) { | 
|  | if (root->defrag_max.objectid > root->defrag_progress.objectid) | 
|  | goto done; | 
|  | if (root->defrag_max.type > root->defrag_progress.type) | 
|  | goto done; | 
|  | if (root->defrag_max.offset > root->defrag_progress.offset) | 
|  | goto done; | 
|  | ret = 0; | 
|  | } | 
|  | done: | 
|  | if (ret != -EAGAIN) { | 
|  | memset(&root->defrag_progress, 0, | 
|  | sizeof(root->defrag_progress)); | 
|  | root->defrag_trans_start = trans->transid; | 
|  | } | 
|  | return ret; | 
|  | } |