blob: eb967a371110e327e8fa0ee5f1df9008aff6ece5 [file] [log] [blame]
/* SCTP kernel reference Implementation
* Copyright (c) 1999-2000 Cisco, Inc.
* Copyright (c) 1999-2001 Motorola, Inc.
*
* This file is part of the SCTP kernel reference Implementation
*
* (It's really SHA-1 but Hey I was tired when I created this
* file, and on a plane to France :-)
*
* The SCTP reference implementation is free software;
* you can redistribute it and/or modify it under the terms of
* the GNU General Public License as published by
* the Free Software Foundation; either version 2, or (at your option)
* any later version.
*
* The SCTP reference implementation is distributed in the hope that it
* will be useful, but WITHOUT ANY WARRANTY; without even the implied
* ************************
* warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
* See the GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with GNU CC; see the file COPYING. If not, write to
* the Free Software Foundation, 59 Temple Place - Suite 330,
* Boston, MA 02111-1307, USA.
*
* Please send any bug reports or fixes you make to the
* email address(es):
* lksctp developers <lksctp-developers@lists.sourceforge.net>
*
* Or submit a bug report through the following website:
* http://www.sf.net/projects/lksctp
*
* Written or modified by:
* Randall Stewart <rstewar1@email.mot.com>
* kmorneau@cisco.com
* qxie1@email.mot.com
*
* Based on:
* Randy Stewart, et al. SCTP Reference Implementation which is licenced
* under the GPL.
*
* Any bugs reported given to us we will try to fix... any fixes shared will
* be incorporated into the next SCTP release.
*/
#include <linux/types.h>
#include <linux/kernel.h>
#include <linux/fcntl.h>
#include <asm/string.h> /* for memcpy */
#include <linux/sched.h> /* dead chicken for in.h */
#include <linux/in.h> /* for htonl and ntohl */
#include <net/sctp/sla1.h>
void SLA1_Init(struct SLA_1_Context *ctx)
{
/* Init the SLA-1 context structure. */
ctx->A = 0;
ctx->B = 0;
ctx->C = 0;
ctx->D = 0;
ctx->E = 0;
ctx->H0 = H0INIT;
ctx->H1 = H1INIT;
ctx->H2 = H2INIT;
ctx->H3 = H3INIT;
ctx->H4 = H4INIT;
ctx->TEMP = 0;
memset(ctx->words, 0, sizeof(ctx->words));
ctx->howManyInBlock = 0;
ctx->runningTotal = 0;
}
void SLA1processABlock(struct SLA_1_Context *ctx,unsigned int *block)
{
int i;
/* init the W0-W15 to the block of words being
* hashed.
*/
/* step a) */
for (i = 0; i < 16; i++)
ctx->words[i] = ntohl(block[i]);
/* now init the rest based on the SLA-1 formula, step b) */
for (i = 16; i < 80; i++)
ctx->words[i] =
CSHIFT(1, ((ctx->words[(i-3)]) ^
(ctx->words[(i-8)]) ^
(ctx->words[(i-14)]) ^
(ctx->words[(i-16)])));
/* step c) */
ctx->A = ctx->H0;
ctx->B = ctx->H1;
ctx->C = ctx->H2;
ctx->D = ctx->H3;
ctx->E = ctx->H4;
/* step d) */
for (i = 0; i < 80; i++) {
if (i < 20) {
ctx->TEMP = ((CSHIFT(5, ctx->A)) +
(F1(ctx->B, ctx->C, ctx->D)) +
(ctx->E) +
ctx->words[i] +
K1
);
} else if (i < 40) {
ctx->TEMP = ((CSHIFT(5, ctx->A)) +
(F2(ctx->B, ctx->C, ctx->D)) +
(ctx->E) +
(ctx->words[i]) +
K2
);
} else if (i < 60) {
ctx->TEMP = ((CSHIFT(5, ctx->A)) +
(F3(ctx->B, ctx->C, ctx->D)) +
(ctx->E) +
(ctx->words[i]) +
K3
);
} else {
ctx->TEMP = ((CSHIFT(5, ctx->A)) +
(F4(ctx->B, ctx->C, ctx->D)) +
(ctx->E) +
(ctx->words[i]) +
K4
);
}
ctx->E = ctx->D;
ctx->D = ctx->C;
ctx->C = CSHIFT(30, ctx->B);
ctx->B = ctx->A;
ctx->A = ctx->TEMP;
}
/* step e) */
ctx->H0 = (ctx->H0) + (ctx->A);
ctx->H1 = (ctx->H1) + (ctx->B);
ctx->H2 = (ctx->H2) + (ctx->C);
ctx->H3 = (ctx->H3) + (ctx->D);
ctx->H4 = (ctx->H4) + (ctx->E);
}
void SLA1_Process(struct SLA_1_Context *ctx, const unsigned char *ptr, int siz)
{
int numberLeft, leftToFill;
numberLeft = siz;
while (numberLeft > 0) {
leftToFill = sizeof(ctx->SLAblock) - ctx->howManyInBlock;
if (leftToFill > numberLeft) {
/* can only partially fill up this one */
memcpy(&ctx->SLAblock[ctx->howManyInBlock],
ptr, numberLeft);
ctx->howManyInBlock += siz;
ctx->runningTotal += siz;
break;
} else {
/* block is now full, process it */
memcpy(&ctx->SLAblock[ctx->howManyInBlock],
ptr, leftToFill);
SLA1processABlock(ctx, (unsigned int *) ctx->SLAblock);
numberLeft -= leftToFill;
ctx->runningTotal += leftToFill;
ctx->howManyInBlock = 0;
}
}
}
void SLA1_Final(struct SLA_1_Context *ctx, unsigned char *digestBuf)
{
/* if any left in block fill with padding
* and process. Then transfer the digest to
* the pointer. At the last block some special
* rules need to apply. We must add a 1 bit
* following the message, then we pad with
* 0's. The total size is encoded as a 64 bit
* number at the end. Now if the last buffer has
* more than 55 octets in it we cannot fit
* the 64 bit number + 10000000 pad on the end
* and must add the 10000000 pad, pad the rest
* of the message with 0's and then create a
* all 0 message with just the 64 bit size
* at the end and run this block through by itself.
* Also the 64 bit int must be in network byte
* order.
*/
int i, leftToFill;
unsigned int *ptr;
if (ctx->howManyInBlock > 55) {
/* special case, we need to process two
* blocks here. One for the current stuff
* plus possibly the pad. The other for
* the size.
*/
leftToFill = sizeof(ctx->SLAblock) - ctx->howManyInBlock;
if (leftToFill == 0) {
/* Should not really happen but I am paranoid */
/* Not paranoid enough! It is possible for leftToFill
* to become negative! AAA!!!! This is another reason
* to pick MD5 :-)...
*/
SLA1processABlock(ctx, (unsigned int *) ctx->SLAblock);
/* init last block, a bit different then the rest :-) */
ctx->SLAblock[0] = 0x80;
for (i = 1; i < sizeof(ctx->SLAblock); i++) {
ctx->SLAblock[i] = 0x0;
}
} else if (leftToFill == 1) {
ctx->SLAblock[ctx->howManyInBlock] = 0x80;
SLA1processABlock(ctx, (unsigned int *) ctx->SLAblock);
/* init last block */
memset(ctx->SLAblock, 0, sizeof(ctx->SLAblock));
} else {
ctx->SLAblock[ctx->howManyInBlock] = 0x80;
for (i = (ctx->howManyInBlock + 1);
i < sizeof(ctx->SLAblock);
i++) {
ctx->SLAblock[i] = 0x0;
}
SLA1processABlock(ctx, (unsigned int *) ctx->SLAblock);
/* init last block */
memset(ctx->SLAblock, 0, sizeof(ctx->SLAblock));
}
/* This is in bits so multiply by 8 */
ctx->runningTotal *= 8;
ptr = (unsigned int *) &ctx->SLAblock[60];
*ptr = htonl(ctx->runningTotal);
SLA1processABlock(ctx, (unsigned int *) ctx->SLAblock);
} else {
/* easy case, we just pad this
* message to size - end with 0
* add the magic 0x80 to the next
* word and then put the network byte
* order size in the last spot and
* process the block.
*/
ctx->SLAblock[ctx->howManyInBlock] = 0x80;
for (i = (ctx->howManyInBlock + 1);
i < sizeof(ctx->SLAblock);
i++) {
ctx->SLAblock[i] = 0x0;
}
/* get last int spot */
ctx->runningTotal *= 8;
ptr = (unsigned int *) &ctx->SLAblock[60];
*ptr = htonl(ctx->runningTotal);
SLA1processABlock(ctx, (unsigned int *) ctx->SLAblock);
}
/* Now at this point all we need do is transfer the
* digest back to the user
*/
digestBuf[3] = (ctx->H0 & 0xff);
digestBuf[2] = ((ctx->H0 >> 8) & 0xff);
digestBuf[1] = ((ctx->H0 >> 16) & 0xff);
digestBuf[0] = ((ctx->H0 >> 24) & 0xff);
digestBuf[7] = (ctx->H1 & 0xff);
digestBuf[6] = ((ctx->H1 >> 8) & 0xff);
digestBuf[5] = ((ctx->H1 >> 16) & 0xff);
digestBuf[4] = ((ctx->H1 >> 24) & 0xff);
digestBuf[11] = (ctx->H2 & 0xff);
digestBuf[10] = ((ctx->H2 >> 8) & 0xff);
digestBuf[9] = ((ctx->H2 >> 16) & 0xff);
digestBuf[8] = ((ctx->H2 >> 24) & 0xff);
digestBuf[15] = (ctx->H3 & 0xff);
digestBuf[14] = ((ctx->H3 >> 8) & 0xff);
digestBuf[13] = ((ctx->H3 >> 16) & 0xff);
digestBuf[12] = ((ctx->H3 >> 24) & 0xff);
digestBuf[19] = (ctx->H4 & 0xff);
digestBuf[18] = ((ctx->H4 >> 8) & 0xff);
digestBuf[17] = ((ctx->H4 >> 16) & 0xff);
digestBuf[16] = ((ctx->H4 >> 24) & 0xff);
}